4Sum
Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target?
Find all unique quadruplets in the array which gives the sum of target.
Notice
Elements in a quadruplet (a,b,c,d) must be in non-descending order. (ie, a ≤ b ≤ c ≤ d) The solution set must not contain duplicate quadruplets.
Example
Given array S = {1 0 -1 0 -2 2}, and target = 0. A solution set is:
(-1, 0, 0, 1)
(-2, -1, 1, 2)
(-2, 0, 0, 2)
Notes:
- Fixed two pointers and then user two pointers
- Ignore duplicate ones
- Time: O(n^3)
public List<List<Integer>> fourSum(int[] nums, int target) {
if (nums == null || nums.length < 4) {
return Collections.emptyList();
}
Arrays.sort(nums);
List<List<Integer>> result = new ArrayList<>();
for (int i = 0; i < nums.length-3; ++i) {
if (i == 0 || i > 0 && nums[i] != nums[i-1]) {
for (int j = i+1; j < nums.length-2; ++j) {
if (j == i+1 || j > i+1 && nums[j] != nums[j-1]) {
int p = j+1;
int q = nums.length-1;
while(p < q) {
int sum = nums[i] + nums[j] + nums[p] + nums[q];
if (sum == target) {
result.add(Arrays.asList(nums[i], nums[j], nums[p], nums[q]));
while(p < q && nums[p] == nums[p+1]) {
p++;
}
while(p < q && nums[q] == nums[q-1]) {
q--;
}
p++;
q--;
} else if (sum < target) {
p++;
} else {
q--;
}
}
}
}
}
}
return result;
}